Answer to Question 10

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a.

b.

XC = 1 (2 p   120 256 10-6) = 5.18 W

XL = 2 p 120 380 10-3 = 211 W

 Z2 = 582 + (211 5.18)2 = 45725

 Z = 213 W

 

c.

 I = V/Z = 15 213 = 0.0701 A (= 70.1 mA)

 

d.

tan f = (211 5.18)  58 = 3.549

f = tan-1 3.549 = 74.26o

 

e.

      Z2 = R2 + XL2 = 482 + 2112 = 46825

Z = 216 ohms

tan f =  216 58 = 3.73

 f = tan-1 3.730 = 75.0o