Answer to Question 3

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  a. XL = 2pfL = 2 p 300 0.4 = 754 ohms

 

 b. 1/Z2 = 1/7542 + 1/2002 = 2.68 10-5 ohm-2

      Z2 = 37371 ohm2 Z = 193 W

 

 c. I = 6.0 193 = 0.031 A (= 31 mA)