Answer to Question 2

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  a. Kirchhoff II: VR1 + VR2 + -Vin = 0

 

 b. Vout = 12        (470)      = 8.17 V

                           220 + 470

 

 c. Treat load as two parallel resistors

   1  +   1    = 8.79 10-3 W-1

   R   470    150

   R = 114 W

    Put this value into the voltage divider equation:

   Vout = 12      114        = 4.10 V

                       220 + 114