Tutorial 8 - Circuit Theorems |
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Learning Objective |
To learn about constant voltage and current sources. To apply Thévenin’s Theorem; To apply Norton's Theorem |
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Key Question |
What are constant voltage and constant current sources? What is Thévenin’s Theorem? What is Norton's Theorem? |
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Constant Voltage and Constant Current SourcesWhen we buy a 9 V battery, we want it to supply 9 V to the device throughout its life. In effect we want it to be a constant voltage supply. We want it to have a voltage of 9 V, whatever current is drawn.
An ideal voltage source is a source that provides a constant voltage, whatever current is drawn, or whatever current is supplied to the terminals.
The circuit symbol for a constant voltage source is shown below:
We can plot a graph of the voltage against the current:
A perfect battery behaves as a constant voltage source. The nearest thing to a perfect battery is a lead-acid car battery. In the lab, we can assume that most sources are ideal constant voltage sources, provided that the current taken by the circuit is low; the voltage does not change measurably.
A constant current source is one that provides the same current, whatever the voltage. An ideal constant current circuit is one that has infinite internal resistance.
We can plot a graph of the voltage against the current:
Constant current sources can be made using electronic circuits, for example the circuit below:
Op amp circuits can also provide constant current sources.
Real sources do not behave like this. Norton’s and Thévenin's Theorems help us to analyse circuits that do not have perfect constant voltage or constant current sources.
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Thévenin’s Theorem
The same ideas also occurred to Hermann von Helmholtz (1821 – 1894), a German physicist and physician, but Thévenin’s name is attached to the theorem.
Thévenin’s Theorem states:
The current in any branch of a network is that which would result if an EMF equal to the potential difference across a break made in the branch, were introduced to the branch, all other EMFs removes and represented by the internal resistances of the sources.
In other words we treat any circuit, however complicated, as a Perfect battery in series with an internal resistor.
You could use a battery symbol to replace the constant voltage source.
Thévenin's Theorem allows us to simplify more complex circuits, and can be easier to use than Kirchhoff’s Laws. There are certain steps that we have to take to simplify a network:
The internal resistance equation is useful:
Thévenin VoltageWhat are the Thévenin voltage (Vth) and the Thévenin resistance (Rth) of this circuit?
So the first thing to do is to remove the resistor R1 next to A. We can do this by disconnecting wire AB. This means that there is no current flowing through R1.
Now we work out the voltage across the gap AB. We can do this with the voltage divider equation:
We can say that the Thévenin voltage is now 7.5 V. Thévenin ResistanceNow we need to remove the source of EMF and “look back” into the circuit. The EMF is shorted out.
Let's make this a bit more "user friendly".
R2 + R3 = 1000 + 1000 = 2000 W
Parallel combination = 1000 W
Total resistance = 1000 + 1000 = 2000 W
Therefore the Thévenin resistance is 2000 W
Now you have a go… |
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Norton’s Theorem
A very similar finding was derived by Hans Ferdinand Mayer (1895 – 1980), a German electrical engineer.
Norton’s Theorem states:
The current that flows in any branch of a network is the
same as that which would flow in the branch is it were connected across
a source of electrical energy, the short-circuit current of which is
equal to the current that would flow in a short circuit across the
branch, and the internal resistance of which is equal to the resistance
which appears across the open-circuited branch terminals.
Got that?
In other words, any collection of batteries and resistors can be treated as a single ideal current source in parallel with a resistor, r (or in the diagram below, RNO).
So how do we go about using Norton’s Theorem? Consider this network of a constant voltage and several resistors.
It’s actually the identical circuit to the one we used with Thévenin. The first thing we do is short-circuit AB. So let’s do that:
Then we add an ammeter to determine the current in AB. Actually a perfect ammeter has zero resistance, so acts as a short-circuit.
Now remove the source of EMF and replace it with a resistor of the same value as its internal resistance. Then remove the connection AB and “look in”.
Then work out the equivalent resistance. We have already shown that it’s 2 kW. So our Norton circuit becomes:
If we connect a Norton equivalent source to a load, R, we get:
We can write an expression for the Norton current:
This is our Norton Equivalent network:
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