Answer to Question 1

 

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When a coil of wire carries a current of 4.0 A that decays to zero in 0.15 s, an EMF of 10.0 V is measured for the duration.  What is the mutual inductance?

Formula:

Rate of change of current = (0 A - 4.0 A) 0.15 s = - 26.7 A s-1

 

10 V = -M - 26.7 A s-1

M = 10 26.7 A s-1 = 0.375 H = 0.38 H (2 s.f.)