Answer to Question 2

 

Back

The mutual inductance between two coils is 240 mH.  The current in Coil 1 changes from 15 A to 6.0 A in 12 ms.  Calculate:

(a) The average EMF induced in Coil 2;

(b) The change of flux linked with Coil 2 which consists of 400 turns.

 

(a) Formula:

Rate of change of current = (6.0 A - 15.0 A) 12 10-3 s = - 750 A s-1

 

E = -240 10-3 H - 750 A s-1 = 180 V

 

(b) Formula:

DF = 9.0 A 0.24 H 400 = 5.4 10-3 Wb = 5.4 mWb