Tutorial 2  Magnetic Quantities 

Learning Objectives 
To review and define the terms used in electromagnetism. To make quantitative links between electrical currents and magnetism. 

Key Questions 
What are the terms used in magnetism? How is an electric current linked with a magnetic field? 

Magnetic Quantities If we look at a magnetic field, we find that the field lines are close together near the poles of the bar magnet. Here the field strength is high. If we move away from the ends of the magnet, the field lines are further apart, so the magnetic field strength is less. Look at the picture:
The weak magnetic field has three field lines going through a wide circle. The magnetic field strength has a low value. The strong magnetic field has seven field lines going through a circle of much smaller diameter. The lines are more concentrated. The magnetic field strength has a much higher value.
The total number of field lines is referred to as magnetic flux. It is defined as the number of field lines passing through a surface. It has the physics code F ("Phi", a Greek upper case letter 'F' or 'Ph'). The units are Weber (Wb).
The magnetic field strength is referred to as flux density. It is a vector quantity, so has a direction as well as a value. It is defined as the flux per unit area. This definition gives the equation:
The physics code is B and the units are Tesla (T), or Weber per square metre (Wb m^{2}). 1 T = 1 Wb m^{2}
The flux, F, is given by rearranging the equation:


The Magnetic Field Strength of an Electric Current Consider a solenoid of n turns per metre which is carrying a current of I amps.
Note that the term n is turns per metre. So you need to divide the total number of turns by the length.
If we measure the flux density in the solenoid well away from the ends, we find that: B µ I and B µ n
The direct proportionality is shown by these graphs:
So we can write: B µ nI There is a constant of proportionality which is called the permeability of free space. It given the physics code m_{0} ("munought"  the symbol 'm' is 'mu', a Greek lower case letter 'm'). The units for the permeability of free space are Henry per metre (H m^{1}) m_{0} = 4p × 10^{7} H m^{1} = 1.257 × 10^{6} H m^{1}
Do not mix up the permeability of free space m_{0} with the permittivity of free space e_{0}. The two words sound similar.
Strictly speaking, the permeability of free space applies to a vacuum. However the value in air is very similar.
In some calculators, keying in "4p ×10()7" gives a syntax error. Key in "4p × 1 ×10()7" or "4 ×10()7 × p and it will work.
We can write an equation for this:
In some textbooks this idea is approached using the magnetomotive force. It is given the physics code F_{m} and the units are ampere turns. Since turns is dimensionless, it is the same as amp (A). The equation is given as: F_{m} = NI In this context the magnetic field intensity (H) is given in this equation:
Magnetic field intensity has the units amp per metre (A m^{1}).
The term N/l is the term turns per metre. Notice that a different physics code for magnetic field intensity is used here, because it has not taken into account the permeability of free space. The argument then develops the idea of the ratio B/H as a constant, i.e.
In the end it all ends up the same.
Linking with Flux Since
we can write an equation that tells us the flux from a solenoid:


Adding a Core to a Solenoid The answer to Question 6 showed that a heavy current would be needed to make magnetic field of the coil as strong as that of a magnet commonly found in a school or college Physics laboratory. The current would probably burn the coil out. Thus electromagnetism would be just a physics curiosity instead of something really useful. We can strengthen the magnetic field considerably by adding a core. The core needs to be made of a magnetic material. If we put in a core of nonmagnetic material, there is no change in the magnetic field strength.
The increase in the magnetic field strength depends on the material. The factor by which the magnetic field strength is increased is called the relative permeability. It is given the physics code m_{r} ("muarr") and there are no units; it's just a number. The definition or relative permeability is:
For a vacuum, m_{r} = 1. The relative permeability for air, m_{r} = 1.00000037, so it's the same. All nonmagnetic materials have a relative permeability of about 1.0; it's only when we go to several significant figures that tiny variations are seen. In these notes, all nonmagnetic materials will be considered to have m_{r} = 1.00.
The equation that links magnetic field strength to current in a solenoid now becomes:
The product of the permeability of free space and relative permeability is the absolute permeability or (simply) permeability. It is give the physics code m and the units are Henry per metre (H m^{1}). The equation is:
The table below shows some values for different nonmagnetic and magnetic materials:
Data from Wikipedia
You can see from your answers to questions 7 and 8 that the current needed to produce a magnetic field of 0.4 T is much less with the iron core than the value without the iron core. The graph below shows a flux density against current graph for no material, a iron with a permeability of 5000, and cobaltiron with a permeability 18000.
Notice that the graphs for the cores are not linear, but the gradient decreases. This is because the materials become saturated, as all the domains line up. The graphs are linear when the currents are low. However the model works for when the currents are low, which is most of the time. 

Magnetic Field of a Flat Coil Consider a flat coil of N turns, and radius r metres. It is carrying a current of I amps. The current is going clockwise as we look at it.
The magnetic field looks like this:
As the coil is circular, all the vector components of the flux density add up at the centre, where the maximum magnetic field is measured.
The flux density at the centre is directly proportional to the current, I and the number of turns, N. It is inversely proportional to the radius, r, of the coil.
The formula for the flux density at the centre is this:
The above calculation involved a point right in the middle of the coil. What happens if we move a distance, z, along the axis of the coil?
The flux density at z metres from the centre, B_{z} is given by a more complex looking equation:
Any term raised to the power 3/2 means it's the square root of the cube of the term. For example 4^{3/2} = Ö64 = 8.
The derivations of the equations above are quite involved, and will no doubt form part of a first year university lecture. We will look at Helmholtz coils (two parallel flat coils a short distance apart) in a later tutorial. 



