Answer to Question 1

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A light coil of dimensions 3.0 5.0 cm with 500 turns is placed in a magnetic field of flux density 14 mT.  A steady current of 0.25 A flows through it.  Calculate:

(a) The maximum torque;

(b) The torque when the coil has turned through 27o.

(a) t = 14 10-3 T 15 10-4 m2 0.25 A 500 = 2.625 10-3 N m = 2.6 10-3 N m (2 s.f.)

 

(b) t = 2.625 10-3 N m cos 27o = 2.3 10-3 N m