Answer to Question 3 |
A motor has an armature of 200 turns of rectangular form 4 cm × 5 cm. The armature is placed in a magnetic field of flux density 0.15 T and a current of 1.5 A is flowing through it. The motor is turning at 2400 rpm. Calculate the power. |
P = BANIw f = 2400 ÷ 60 = 40 Hz. w = 2p × 40 Hz = 251 rad s^{-1} A = 0.040 × 0.050 = 2.0 × 10^{-3} m^{2} P = 0.15 T × 2.0 × 10^{-3} m^{2} × 200 × 1.5 A × 251 rad s^{-1} = 23 W |