Answer to Question 2

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An electron accelerated to 6.0 106 m/s is deflected by a magnetic field of strength 0.82 T.   It makes an angle of 76o to the field.

(a) Calculate the force acting on the electron now.

(b) Calculate the forward velocity as it makes its helical path along the magnetic field.

 

(a) F = 0.82 T 1.6 10-19 C 6.0 106 m s-1 sin 76 = 7.64 10-13 N = 7.6 10-13 N (2 s.f.)

 

(b) v = 6.0 106 m s-1 cos 76 = 1.45 106 m s-1 = 1.5 106 m s-1 (2 s.f.)