Answer to Question 5

 

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What is the radius of curvature of the electron in question 4, if the magnetic field has a flux density of 0.035 T?

 

Formula:

r = 9.11 10-31 kg    2.14 107 m s-1

            0.035 T 1.602 10-19 C         

 

r =  3.5 10-3 m (2 s.f. as the flux density is to 2 s.f.) = 3.5 mm