Answer to Question 5

 

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An inductor of inductance 0.14 H is connected to a 12 V supply of negligible internal resistance.  The exponential rise of the measured voltage is studied and at a certain time, it is found that the measured voltage is 2.5 V.  Calculate the rate of change of the current at this time.

EMF = 12 V - 2.5 V = 9.5 V

dI/dt = E/L = 9.5 V 0.14 H = 68 A s-1