Answer to Question 2

 

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The coil providing the magnetic field has 200 turns.   The magnetic flux is 0.14 T.

(a)  Calculate the magnetic field strength.

(b) Calculate the current.

(a) Formula:

l = 2 p 7.5 10-2 m = 0.471 m

 

H =  [5.98 106  H-1 3.14 10-4 m2 0.14 T] 0.471 m = 558 A m-1

 

(b) Formula:

I = (0.471 m 558 A m-1) 200 = 1.31 A