Answer to Question 7

 

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Calculate the magnetomotive force across each reluctance in Question 5 using your answer to Question 6 (b).  Is your answer consistent with your answer to 6 (a)?

 

Fm = 300 turns 0.75 A = 225 A turns

 

F  = 225 A turns  3.09 106 H-1  = 7.28 10-5 Wb

Fm = SF

 

S1  = 1.82 106 H-1

 

Fm1 = 1.82 106 H-1 7.28 10-5 Wb = 133 A turns

 

 

S2  = 1.27 106 H-1

 

Fm2 = 1.27 106 H-1   7.28 10-5 Wb = 92.5 A turns

 

 

Stot = 1.82 106 H-1 + 1.27 106 H-1 = 3.09 106 H-1

 

Fmtot = 3.1 106 H-1 7.28 10-5 Wb =  225 A turns

 

The answers are consistent.