Answer to Question 2

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(a) t = 470 10-6 F 150 103 W = 70.5 s

(b) The voltage is one half, so we have 1 half-life.  t1/2 = 0.693 70.5 s = 48.9 s 49 s (2 s.f.)

(c) The voltage is one quarter, so we have 2 half-lives.  t = 97.7 s 98 s (2 s.f.)

(d) V = 0.37 12 V = 4.4 V

(e) Discharge time = 5 t = 5 70.5 = 352.5 s 350 s (2 s.f.)